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[Cites 0, Cited by 0] [Section 12A] [Entire Act]

Union of India - Subsection

Section 12A(11) in The Merchant Shipping (Prevention of Pollution by Oil from Ships) Rules, 2010

(11)As an alternative to sub-rule (6) and either of sub-rules (7) or (8), ships shall comply with the accidental oil fuel outflow performance standard specified below, namely:-
(a)the level of protection against oil fuel pollution in the event of collision or grounding shall be assessed on the basis of the mean oil outflow parameter as follows:
OM 0.0157-1.14E-6C for 600 m3≤ C < 5,000 m3OM ≤0.010 for C ≥ 5,000 m3Where OM = mean oil outflow parameter;C = total oil fuel volume;
(b)the following general assumption shall apply when calculating the mean oil outflow parameter, namely:-
(i)the ship shall be assumed loaded to the partial load line draught dp without trim or heel;
(ii)all oil fuel tanks shall be assumed loaded to 98% of their volumetric capacity;
(iii)the nominal density of the oil fuel (pn) shall generally be taken as 1,000 kg/m3 and if the density of the oil fuel is specifically restricted to a lesser value, the lesser value may be applied; and
(iv)for the purpose of these outflow calculations, the permeability of each oil fuel tank shall be taken as 0.99, unless proven otherwise;
(c)the following assumptions shall be used when combining the oil outflow parameters, namely:-
(i)the mean oil outflow shall be calculated independently for side damage and for bottom damage and then combined into a non-dimensional oil outflow parameter OM, as follows:
OM = (0.4 OMS + 0.6 MB)/Cwhere:OMS = mean outflow for side damage, in m3OMb = mean outflow for bottom damage, in m3C = total oil fuel volume;
(ii)for bottom' damage, independent calculations for mean outflow shall be done for 0 m and 2.5 m tide conditions, and then combined as follows:
OMB= 0.7 OMB(0)) + 0.30MB(2.5))where:OMB(0)) = mean outflow for 0 m tide condition, andOMB(2.5)) = mean outflow for minus 2.5 in tide condition, in m3
(d)the mean outflow for side damage OMS shall be calculated as follows:
n
Oms| ∑ Ps(i)Os(i) [m3]
iwhere:i = represents each oil fuel tank under consideration;n = total number of oil fuel tanks;Ps(i) = the probability of penetrating oil fuel tank i from side damage, calculated in accordance with clause(f);Os(i) = the outflow, in m3, from side damage to oil fuel tank i, which is assumed equal to the total volume in oil fuel tank i at 98% filling;
(e)the mean outflow for bottom damage shall be calculated for each tidal condition as follows:
n
(i) Omb(0)| ∑ PB(i)OB(i)CDB(i)[m3]
iwhere:i = represents each oil fuel tank under consideration;n = total number of oil fuel tanks;Pb(i) = the probability of penetrating oil fuel tank i from Bottom damage, calculated in accordance with clause (g);Ob(i) = the outflow from oil fuel tank i, in m3, calculated in accordance with sub-clause (iii); andCdb(i) = factor to account for oil capture as defined in item (D) of sub-clause(iii);n
(ii) Omb(2.5)| ∑ PB(i)OB(i)CDB(i)[m3]
iwhere:i,n,Pb(i)and Cdb(i) = as defined in subparagraph (i)aboveOb(i) = the outflow from oil fuel tank i, in m3, after tidal change;
(iii)the oil outflow 08(i) for each oil fuel tank shall he calculated based on pressure balance principles,in accordance with the following assumptions, namely:-
(A)the ship shall be assumed stranded with zero trim and heel, with the stranded draught prior to tidal change equal to the partial load line draught dp
(B)the oil fuel level after damage shall be calculated as follows:
hf {(dp + tc + z1()}/pnwhere:hF = the height of the oil fuel surface above Z1, in metters;tc = the tidal change, in m Reductions in tide shall be expressed as negative values;Z1 = the height of the lowest point in the oil fuel tank above the baseline, in m;Ps = density of seawater, to be taken as 1,02S kg/m\and,Pn = nominal density of the oil fuel, as defined in sub-clause (iii) of clause (b);
(C)the oil outflow Ob(i) for any tank bounding the bottom shell plating shall be taken not less than the following formula, but no more than the tank capacity:
Ob(i)=HwAwhere:Hw = 1.0 m, when Yb = 0Hw = BB/50 but not greater than 0.4 m, when Yb is Greater than Bb/5 or 11.5m, whichever is less,"Hw" is to be measured upwards from the midship flat bottom line and in the tum of the bilge area and at locations without a clearly defined tum of the bilge, Hw is to be measure from a line parallel to the midship flat bottom, as shown for distance "h" in Figure I.For Yb values outboard BB/5 or 11.5 m, whichever is less, Hw = is to be linearly interpolated.Yb = the minimum value of YB over the length of the oil fuel tank, where at any given location, Yb is the transverse distance between the side shell at waterline db and the tank at or below waterline DbA = the maximum horizontal projected area of the oil fuel tank up to the level of Hw from the bottom of the tank.Hw = BB/50 but not greater than 0.40m.
(D)in the case of bottom damage, a portion from the outflow from an oil fuel tank may be captured by non-oil compartments and this effect is approximated by application of the factor CDB(i) for each tank, which shall be taken as follows:
CDB = 0.6 for oil fuel tanks bounded from below by non-oil compartments;CDB(i) = 1 otherwise.
(f)the probability Ps of breaching a compartment from side damage shall be calculated as follows:
(i)PS = PSL PSV Pst
where:PSL = (I-PSf - PSa) = probability the damage will extend into the longitudinal zone bounded by Xa and Xr;PSv = (I - PSu PSl = probability the damage will extend into the vertical zone bounded by Zl and zu;PST = (I - PSy) = probability the damage will extend Transversely beyond the boundary defined by y;
(ii)Psa, PSf, PSl and PSI shall be determined by linear interpolation from the table of probabilities for side damage provided in sub-clause (iii), and PSy shall be calculated from the formulas provided in the said sub-clause (iii), where:
PSa = the probability the damage will lie entirely aft of location Xa/L;PSf = the probability the damage will lie entirely forward of location Xf/L;PS1 = probability the damage will lie entirely below the tank;PSu = probability the damage will lie entirely above the tank; andPSy = probability the damage will lie entirely outboard the tank and compartment boundaries Xa, Xf, Zl Zu and y shall be developed as follows:Xa = the longitudinal distance from aft terminal of L to the aft most point on the compartment being considered, in m;Xf the 10ngitlKiinai distance from aft terminal of L to the foremost point on the compartment being considered, in in;Zl the vertical distance from the moulded baseline to the lowest point on the compartment being considered, in m Where Zl, is greater than Ds, Z1, shall be taken as Ds;Zu = the vertical distance from the moulded baseline to the highest point on the compartment being considered, in m Where Zu is greater than Ds, Zu shall be taken as Ds; and,y = the minimum horizontal distance measured at right angles to the centreline between the compartment under consideration and the side shell, in M1:In way of the turn of the bilge, y need not to be considered below a distance h above baseline, where h is lesser of B/l0, 3 m or the top of the tank.
(iii)Table of Probabilities for side damage
Xa/L Psa Xf/L Psf Z1/Ds Ps1 Zu/Ds PsU
0,00 0,000 0,00 0,967 0,00 0,000 0,000 0,968
0,05 0,023 0,05 0,917 0,05 0,000 0,05 0,952
0,10 0,068 0,10 0,867 0,10 0,001 0,10 0,931
0,15 0,117 0,15 0,817 0,15 0,003 0,15 0.905
0,20 0,167 0,20 0,767 0,20 0,007 0.20 0,873
0,25 0,217 0,25 0,717 0,25 0,013 0,25 0,836
0,30 0,267 0,30 0,667 0,30 0,021 0,30 0,789
0,35 0,317 0,35 0,617 0,35 0,034 0,35 0,733
0,40 0,367 0,40 0,567 0,40 0,055 0,40 0,670
0,45 0,417 0,45 0,517 0,45 0,085 0,45 0,599
0,50 0,467 0,50 0,467 0,50 0,123 0,50 0,525
0,55 0,517 0,55 0,417 0,55 0,172 0,55 0,452
0,60 0,567 0,60 0,367 0,60 0,226 0,60 0,383
0,65 0,617 0,65 0,317 0,65 0,285 0,65 0,317
0,70 0,667 0,70 0,267 0,70 0,347 0,70 0,255
0,75 0,717 0,75 0,217 0,75 0,413 0,75 0,197
0,80 0,767 0,80 0,167 0,80 0,482 0,80 0,143
0,85 0,817 0,85 0,117 0,85 0,553 0,85 0,092
0,90 0,867 0,90 0,068 0,90 0,626 0,90 0,046
0,95 0,917 0,95 0,023 0,95 0,700 0,95 0,013
1,00 0,967 1,00 0,000 1,00 0,775 1,00 0,000
Psy shall be calculated as follows:
Psy= (24.96 - 199.6 Y/Bs) (Y/Bs) For Y/Bs≤ 0.05
Psy= 0.749 + {5 - 44.4 (Y/Bs- 0.05)}{(Y/Bs) - 0.05} For 0.05 < y/Bs< 0.1
Psy= 0.888 + 0.56 (Y/Bs- 0.1) For y/Bs≥ 0.1
Psy is not to be taken greater than 1.
(g)the probability Pb of breaching a compartment from bottom damage shall be calculated as follows:
(i)PB = PBL. PBT. PBV.
where:PBL =(1 - PBT - PBa = probability the damage will extend into the longitudinal zone bounded by Xa and XfPBT(1 - PBP - PB5 = probability the damage will extend into the longitudinal zone bounded by Yp and YsPBv = (1 - PBz = probability the damage will extend Vertically above the boundary defined by z;
(ii)PBa,PBf,PBp,PBs shall be determined by linear interpolation from the table of probabilities for bottom damage provided in sub-clause (iii) of clause (g), and PBz shall be calculated from the formulas provided in sub-clause (iii) of clause(g):
PBa = the probability the damage will lie entirely aft of Location Xa/LPBf = the probability the damage will lie entirely aft of Location Xf/LPBp = probability the damage will lie entirely to port of the tank;PBs = probability the damage will lie entirely to starboard the tank; andPBz = probability the damage will lie entirely below the tank;Provided that for symmetrical tank arrangements, damages are considered for one side of the ship only, in which case, all "y" dimensions are to 'be measured from that side and for asymmetrical arrangements, reference is made to the Explanatory Notes on matters related to the accidental oil outflow performance, adopted by the Organization:Provided further that compartment boundaries Xa, Xf Xp Xs and z shall be developed as follows:Xa and Xf as defined in sub-clause (ii) of clause (f);Yp = the transverse distance from the port-most point on the compartment located at or below the waterline DB, to a vertical plane located BB/2 to starboard of the ship's centreline;Ys = the transverse distance from the starboard-most point on the compartment located at or below the waterline dB, to a vertical plane located BB/2 to starboard of the ship's centreline; andz = the minimum value of z over the length of the compartment, where, at any given longitudinal location, z is the vertical distance from the lower point of the bottom shell at that longitudinal location to· the/lower point of the compartment at that longitudinal location.
(iii)Table' of probabilities for bottom damage
Xa/L PB.a Xp/L PBr Yp/BB PBo Ys/bb PBs,
0,00 0,000 0,00 0,969 0,00 0,844 0,00 0,000
0,05 0,002 0,05 0,953 0,05 0,794 0,05 0,009
0,10 0,008 0,10 0,936 0,10 0,744 0,10 0,032
0,15 0,017 0,15 0,916 0,15 0,694 0,15 0,063
0,20 0,029 0,20 0,894 0,20 0,644 0,20 0,097
0,25 0,042 0,25 0,870 0,25 0,594 0,25 0,133
0,30 0,058 0,30 0,842 0,30 0,544 0,30 0,171
0,35 0,076 0,35 0,810 0,35 0,494 0,35 0,211
0,40 0,096 0,40 0,775 0,40 0,444 0,40 0,253
0,45 0,119 0,45 0,734 0,45 0,394 0,45 0;297
0,50 0,143 0,50 0,687 0,50 0,344 0,50 0,344
0,55 0,171 0,55 0,630 0,55 0,297 0,55 0,394
0;60 0,203 0,60 0,563 0,60 0,253 0,60 0,444
0,65 0,242 0,65 0,489 0,65 0,211 0,65 0,494
0,70 0,289 0,70 0,413 0,70 0,171 0,70 0,544
0,75 0,344 0,75 0,333 0,75 0,133 0,75 0,594
0,80 0,409 0,80 0,252 0,80 0,097 0,80 0,644
0,85 0,482 0,85 0,170 0,85 0,063 0,85 0,694
0,90 0,565 0,90 0,089 0,90 0,032 0,90 0,744
0:95 0,658 0,95 0,026 0,95 0,009 0,95 0,794
1,00 0,761 1,00 0,000 1,00 0,000 1,00 ,0,844
PBz shall be calculated as follows:
PBz= (14.5 - 67 z/Ds) (z/Ds) for z/Ds≤ 0.1
PBz = 0.78 + 1.1 {(z/Ds– 0.1)} for z/Ds> 0.1
PBz is not to be taken greater than 1.
(h)For the purpose of maintenance and inspection, any oil fuel tanks that do not border the outer shell plating shall be located no closer to the bottom shell plating than the minimum value of h in sub rule (6) and no closer to the side shell plating than the applicable minimum value of w in sub rule (7) or (8).